Photo duplicate web search...

Hi peeps,
I've got two naughty photos of a girl who I'm involved with. I'd like to search the net for exact copies of these pics just to see if she's involved in anything risque which I'm unaware of. I've asked her indirectly but she seems rather protective of these pics and avoids giving answers. Worst case scenario is she's an escort who's fallen in love with me.
Is there a site or some software that can help find copies/duplicates of these photos on the net?
I'm getting more and more paranoid by the day!

Would appreciate a nod in the right direction....

Sorry to hear that mate, I hope everything works out well for you.

There are guys on here with phenomenal knowledge of the adult entertainment industry.Just look in some of the threads and maybe PM a couple with the images.I'm sure they will be discrete and you will get your answer and put your mind at rest.I don't know of any software available to the public that could help you so maybe this is your best option.I can't vouch for any other websites either but I have come to realise that 99.9% of the members on here are good people.
I hope all goes well,whatever you find out.

Dreamlander

Tineye is your friend

that site is pretty cool

I just gave it a try using an image of Nicole Graves and it worked a treat, it gave me a few links to sites on which the image had been posted...great link Stevie .

Cheers guys. Just tried Tineye and unfortunately (or fortunately) it hasn't found any matches. I'm going to do the honorable thing and confront her tonight.
I think I'm being reasonable, she's got a stunning figure, amazing greeny bluey eyes, and she's a veritable nymphomaniac. I have every right to be suspicious!

Sounds like you're a lucky bugger to me, but good luck mate, I hope all goes well for you .

Just to add, there's links for add-ons for Firefox and IE here. They let you just right click on any picture you see in your browser window and search for it instead of arsing about pasting in the link or uploading a pic. Hope someone finds this useful